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Fixed some errors in comments.
git-svn-id: svn://136.177.114.72/svn_GW/phreeqc3/branches/concrete@10797 1feff8c3-07ed-0310-ac33-dd36852eb9cd
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Amm.dat
32
Amm.dat
@ -88,10 +88,12 @@ K+ = K+
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Fe+2 = Fe+2
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-gamma 6.0 0
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-dw 0.719e-9
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-Vm -0.3255 -9.687 1.536 -2.379 0.3033 6 -4.21e-2 39.7 0 1 # ref.
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-Vm -0.3255 -9.687 1.536 -2.379 0.3033 6 -4.21e-2 39.7 0 1 # ref. 1
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Mn+2 = Mn+2
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-gamma 6.0 0
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-dw 0.688e-9
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-Vm -1.10 -8.03 4.08 -2.45 1.4 6 8.07 0 -1.51e-2 0.118 # ref. 2
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Al+3 = Al+3
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-gamma 9.0 0
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@ -126,10 +128,10 @@ NO3- = NO3-
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-gamma 3.0 0
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-dw 1.9e-9 219
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-Vm 6.32 6.78 0 -3.06 0.346 0 0.93 0 -0.012 1 # ref. 1
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AmmH+ = AmmH+
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-gamma 2.5 0
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-dw 1.98e-9 377
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-Vm 4.837 2.345 5.522 -2.88 1.096 3 -1.456 75.0 7.17e-3 1 # ref. 1
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#AmmH+ = AmmH+
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# -gamma 2.5 0
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# -dw 1.98e-9 377
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# -Vm 4.837 2.345 5.522 -2.88 1.096 3 -1.456 75.0 7.17e-3 1 # ref. 1
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H3BO3 = H3BO3
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-dw 1.1e-9
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-Vm 7.0643 8.8547 3.5844 -3.1451 -.2000 # supcrt
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@ -257,7 +259,14 @@ NO3- + 2 H+ + 2 e- = NO2- + H2O
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-delta_h -312.130 kcal
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-dw 1.96e-9
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-Vm 7 # Pray et al., 1952, IEC 44. 1146
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AmmH+ = Amm + H+
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NO3- + 10 H+ + 8 e- = NH4+ + 3 H2O
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-log_k 119.077
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-delta_h -187.055 kcal
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-gamma 2.5 0
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-dw 1.98e-9 377
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-Vm 4.837 2.345 5.522 -2.88 1.096 3 -1.456 75.0 7.17e-3 1 # ref. 1
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#AmmH+ = Amm + H+
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NH4+ = NH3 + H+
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-log_k -9.252
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-delta_h 12.48 kcal
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-analytic 0.6322 -0.001225 -2835.76
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@ -269,7 +278,8 @@ AmmH+ = Amm + H+
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# -gamma 2.5 0
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# -Vm 4.837 2.345 5.522 -2.88 1.096 3 -1.456 75.0 7.17e-3 1 # ref. 1
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AmmH+ + SO4-2 = AmmHSO4-
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#AmmH+ + SO4-2 = AmmHSO4-
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NH4+ + SO4-2 = NH4SO4-
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-log_k 1.11
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-Vm 14.0 0 -35.2 0 0 0 12.3 0 -0.141 1 # ref. 2
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H3BO3 = H2BO3- + H+
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@ -1497,7 +1507,7 @@ Quartz
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# and pollution, 2nd Edition: A.A. Balkema Publishers,
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# p. 162-163 and 395-399.
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#
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# Assume soil is 10% K-feldspar by mass in 1 mm spheres (radius 0.5 mm)
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# Assume soil is 10% K-feldspar by mass in 1 mm spheres (radius 0.05 mm)
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# Assume density of rock and Kspar is 2600 kg/m^3 = 2.6 kg/L
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# GFW Kspar 0.278 kg/mol
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#
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@ -1581,7 +1591,7 @@ K-feldspar
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# -parms 6.04 0.1 # m^2/mol Albite, fraction adjusts lab rate to field rate
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# -time 1.5 year in 40
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#
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# Assume soil is 2% Albite by mass in 1 mm spheres (radius 0.5 mm)
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# Assume soil is 2% Albite by mass in 1 mm spheres (radius 0.05 mm)
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# Assume density of rock and Albite is 2600 kg/m^3 = 2.6 kg/L
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# GFW Albite 0.262 kg/mol
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#
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@ -1593,9 +1603,9 @@ K-feldspar
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# Specific area calculation:
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# Volume of sphere 4/3 x pi x r^3 = 5.24e-13 m^3 Albite/sphere
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# Mass of sphere 2600 x 5.24e-13 = 1.36e-9 kg Albite/sphere
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# Moles of Albite in sphere 1.36e-9/0.278 = 5.20e-9 mol Albite/sphere
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# Moles of Albite in sphere 1.36e-9/0.262 = 5.20e-9 mol Albite/sphere
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# Surface area of one sphere 4 x pi x r^2 = 3.14e-8 m^2/sphere
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# Specific area of Albite in sphere 3.14e-8/4.90e-9 = 6.04 m^2/mol Albite
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# Specific area of Albite in sphere 3.14e-8/5.20e-9 = 6.04 m^2/mol Albite
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Albite
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-start
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