Improved docs about boundary conditions treatment for 2D ADI
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@ -253,23 +253,57 @@ yields:
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-C^{t + 1/2}_{i,j} - s_x (C^{t + 1/2}_{i-1,j} - 2C^{t + 1/2}_{i,j} + C^{t + 1/2}_{i+1,j}) = - C^{t+1}_{i,j} + s_y (C^{t+1}_{i,j-1} - 2C^{t+1}_{i,j} + C^{t+1}_{i,j+1})
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\end{equation}
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This scheme only applies to inlet cells without a relation to
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boundaries. Fortunately we already derived both cases of outer left
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and right inlet cell respectively. Hence we are able to redefine each
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$\delta^2$ case in x and y direction, assuming $l_x$ and $l_y$ the be
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the left boundary value and $r_x$ and $r_y$ the right one for each
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direction $x$ and $y$. The equations are exemplary for time level
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$t+1/2$:
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This scheme only applies to inner cells, or else $\forall i,j \in [1,
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n-1] \times [1, n-1]$. Following an analogous treatment as for the 1D
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case, and noting $l_x$ and $l_y$ the constant left boundary values and
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$r_x$ and $r_y$ the right ones for each direction $x$ and $y$, we can
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modify equations [[eqn:sweepX]] for $i=0, j \in [1, n-1]$
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#+NAME: eqn:boundXleft
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\begin{equation}\displaystyle
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-C^t_{0,j} - s_y (C^{t}_{0,j-1} - 2C^{t}_{0,j} + C^{t}_{0,j+1}) = - C^{t+1/2}_{0,j} + s_x (C^{t+1/2}_{1,j} - 3C^{t+1/2}_{0,j} + 2 l_x)
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\end{equation}
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\noindent Similarly for $i=n, j \in [1, n-1]$:
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#+NAME: eqn:boundXright
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\begin{equation}\displaystyle
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-C^t_{n,j} - s_y (C^{t}_{n,j-1} - 2C^{t}_{n,j} + C^{t}_{n,j+1}) = - C^{t+1/2}_{n,j} + s_x (C^{t+1/2}_{n-1,j} - 3C^{t+1/2}_{n,j} + 2 r_x)
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\end{equation}
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\noindent For $i=j=0$:
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#+NAME: eqn:bound00
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\begin{equation}\displaystyle
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-C^t_{0,0} - s_y (C^{t}_{0,1} - 3C^{t}_{0,0} + 2l_y) = - C^{t+1/2}_{0,0} + s_x (C^{t+1/2}_{1,0} - 3C^{t+1/2}_{0,0} + 2 l_x)
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\end{equation}
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Analogous expressions are readily derived for all possible
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combinations of $i,j \in 0\times n$. In practice, wherever an index
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$i$ or $j$ is $0$ or $n$, the centered spatial derivatives in $x$ or
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$y$ directions must be substituted in relevant parts of the sweeping
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equations \textbf{in both the implicit or the explicit sides} of
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equations [[eqn:sweepX]] and [[eqn:sweepY]] by a term
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#+NAME: eqn:bound00
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\begin{equation}\displaystyle
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s(C_{forw} - 3C + 2 bc)
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\end{equation}
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\noindent where $bc$ is the boundary condition in the given direction,
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$s$ is either $s_x$ or $s_y$, and $C_{forw}$ indicates the contiguous
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cell opposite to the boundary. Alternatively, noting the second
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derivative operator as $\partial_{dir}^2$, we can write in compact
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form:
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\begin{equation}
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\systeme{
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\displaystyle \delta^2_d C^{t+1/2}_{0,j} = 2l_x - 3C^{t+1/2}_{0,j} + C^{t+1/2}_{1,j} ,
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\displaystyle \delta^2_d C^{t+1/2}_{n,j} = 2r_x - 3C^{t+1/2}_{n,j} + C^{t+1/2}_{n-1,j} ,
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\displaystyle \delta^2_d C^{t+1/2}_{i,0} = 2l_y - 3C^{t+1/2}_{i,0} + C^{t+1/2}_{i,1} ,
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\displaystyle \delta^2_d C^{t+1/2}_{i,n} = 2r_y - 3C^{t+1/2}_{i,n} + C^{t+1/2}_{i,n-1}
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\displaystyle \partial_x^2 C_{0,j} = 2l_x - 3C_{0,j} + C_{1,j} ,
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\displaystyle \partial_x^2 C_{n,j} = 2r_x - 3C_{n,j} + C_{n-1,j} ,
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\displaystyle \partial_y^2 C_{i,0} = 2l_y - 3C_{i,0} + C_{i,1} ,
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\displaystyle \partial_y^2 C_{i,n} = 2r_y - 3C_{i,n} + C_{i,n-1}
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}
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\end{equation}
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#+LATEX: \clearpage
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* Old stuff
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